LeetCode # 258 Given an integer num, repeatedly add all its digits until the result has only one digit, and return it. Example 1: Input: num = 38 Output: 2 Explanation: The process is 38 --> 3 + 8 --> 11 11 --> 1 + 1 --> 2 Since 2 has only one digit, return it. Constraints: 0 9 && num == 0) { num = sum; sum = 0; } } return sum; } } Result #1 More Algorithm! 👇👇 github.com/ggujangi/ggu.leet-code g..
